I'm currently working on a very tight install.
I was wondering if I could use the drive parameter instead of a resistor? Looking at the specsheet, the blue led has a forward voltage of 3.47, and the fully charged battery will give about 4.1 Volts when pulling 2 amps. With Erv's calculation I'd have to put the Drive at 866 [1023*(3.47/4.1)]. This would be 84.5% of max drive.
Would there be a downside to using this technique?
I know I should measure the exact led voltage instead of using the specsheet, but I simply don't have the equipment needed yet.