What I got from sunriders link is that in parallel the voltage remains the same and the current drops...
1. So if I want to give both main dices 1250 mA I have to configure the CF to output 2500 mA...? (Thats the max anyway.)
Given the fact that the battpack has a max discharge current of 3500 mA I can give up to 1000 mA for the FoC dice without blowing the battpack...?
In a series circuit the current remains the same and the voltage drops...
2. So if I wire both main dices in series I just have to configure the CF to output 1250 mA and both dices get these 1250 mA
I would have 2250 mA left for the FoC led?
Sidenote: Is the voltage drop avoided by the CF because it detects the Vf and outputs the correct one anyway? (Series circuit)
3. Any method prefered, like series over parallel or parallel over series?
Oh and would be kinda nice if someone could answer my previous questions:
1. If I set the CF to lets say 1500 mA and drive two dices either in parallel or series, both get 1500 mA?
(Or is it like 1500 mA + 1500 mA = 3000 mA? Any difference betwenn wiring in series or parallel?)
2. If I give the FoC dice 1500 mA via the resistor a total of 3000 mA (not 4500 mA) will be drawn from the battpack?
Being 1500 mA from RB main dice and 1500 mA from the FoC dice?
Battpack max discharge is 3500 mA, so there wont be any danger?